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Solve the simultaneous equation 6x + 2y = -3, 4x - 3y =11

6x + 2y = -3 (1)*3 4x - 3y = 11 (2)*2 18x + 6y = -9 (1) 8x - 6y = 22 (2) (1) + (2) = 18x +8x + 6y - 6y = -9 + 22 => 26x = 13 => x = 1/2 sub x into (1) => (6 * 0.5) + 2y = -3 3 + 2y = -3 2y = -6 y = -3
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Answered by Aldouz P. • Maths tutor
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AQA GCSE higher specimen paper 1: Question 28

When performing live calculations of examples of questions for the students, I shall begin by writing down an approach to how they should tackle the problem. This will only take a minute and I’ve found doing...
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Answered by Andrew R. • Maths tutor
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Solve the following simultaneous equations: 2y+x=8 , 1+y=2x

This is a very common type of question that might be asked in an exam and there are 3 methods we could use to solve this; by substitution, by elimination (or subtraction) or by using straight line graphs. Th...
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Answered by Ben R. • Maths tutor
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Expand and simplify 2y+3y(5y+3)

BIDMAS Following BIDMAS, multiply the bracket out before the addition of the 2y. 3y(5y+3) = 15y 2 +9y adding the 2y gives the calculation of 15y 2 + 9y +2y = 15y 2 + 11y
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Answered by Emma S. • Maths tutor
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Solve the equation (2X + 3) / (X-4) - (2X - 8) / (2X + 1) = 1

In order to solve this equation we need to find a common denominator for the 2 fractions. It is impossible to name the common denominator while working with unknown variables such as x,y etc. but we know fro...
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Answered by Octavian G. • Maths tutor
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