Top answers

Solve algebraically: 6a+b = 16 and 5a - 2b = 19

6a + b = 16 (1) 5a - 2b = 19 (2) (1) x 2: 12a + 2b =32 (1) + (2): 12a + 2b + 5a - 2b = 32 + 19 = 51 17a = 51 a = 51 / 17 = 3 Substitue a = 3 back into (1): (6 x 3) + b = 16 18 + b = 16 b = 16 - 18 = - 2 Subs...
NR
Answered by Niva R. • Maths tutor
3578 Views

Solve 0=X^2 +5x +4

0= (x + 4)(x + 1) x= - 4 x= - 1
RW
Answered by Rebecca W. • Maths tutor
3280 Views

Show that (4x – 5)^2 – 5x(3x – 8) is positive for all values of x

(4x-5)^2-5x(3x-8) (16x^2-40x+25)-(15x^2-40x) 16x^2-15x^2-40x+40x+25 x^2+25 if x = positive, x^2 will be positive. if x = negative, x^2 will be positive. x^2 is positive for all values of X, +25 will not make...
JM
Answered by Joseph M. • Maths tutor
4162 Views

((2x + 3)/(x-4)) - ((2x-8)/(2x+1)) = 1

x=0.81
AS
Answered by Amelia S. • Maths tutor
3368 Views

You are shown a diagram of a right angled triangle, with the hypotenuse labelled c and the other sides labelled a and b. If a is 7m long and c is 10m long, what is the length of b?

A simple implementation of Pythagoras' Theorem a 2 +b 2 =h 2 , and as in the question c is the hypotenuse, a 2 +b 2 =c 2 . (Side Note - in exams, the question may not specify which length is the hypotenuse -...
WH
Answered by William H. • Maths tutor
4464 Views