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Solve these simultaneous questions: 2y+x =8 and y-2x = -1.

x = 2 y = 3
CL
Answered by Celine L. • Maths tutor
3864 Views

How do you solve the simultaneous equations 3x+y=5 and x-y=3?

The aim of this question is to find x and y by combining these two equations. There are two ways of solving simultaneous equations, elimination and substitution. Elimination can only be used when there are n...
AN
Answered by Andrew N. • Maths tutor
6966 Views

A gardener uses this formula to work out how much he charges to make a lawn. C = (7(14+A))/3. C is the charge in £, A is the area in m^2. He makes a rectangular lawn measuring 12.5 m by 17.6 m. How much does he charge? [3 marks]

Rectangular Lawn of 12.5 x 17.6m. (Draw Rectangle) Area=Length Height A=12.5 17.6 A=220m^2 Substitute into formula: C=(7(14+A))/3 C=(7(14+220))/3 C=(7(234))/3 C=(1638)/3 C=546 The gardener will charge £546.
JF
Answered by Joshua F. • Maths tutor
5116 Views

Factorise f(x) = 6x^3 -7x^2 -x +2 = 0

Try to find first root: f(1) = 6 - 7 -1 + 2 = 0, therefore x-1 is a root. Find quadratic by inspection: (x-1)( )= 6x^3 -7x^2 -x +2 (x-1)(6x^2 - x - 2) Factorise quadratic: (x-1)(2x+1)(3x-2) = 0
TD
Answered by Tutor40745 D. • Maths tutor
10287 Views

Factorise y^2 + 7y + 6

So here we have a quadratic equation because it has the structure a^2 + bx + c. In order to factorise a quadratic we first need to look for two numbers that we can multiply together to get 6 and add together...
VH
Answered by Victoria H. • Maths tutor
14710 Views