Top answers

Solve the simultaneous equations y=2x and y=x+3

As both equations have y on the left hand side we can put the right hand sides equal to each other, so 2x=x+3. We can then subtract x from both sides. This gives 2x-x on the left hand side which is x, and x+...
HC
Answered by Hannah C. • Maths tutor
9782 Views

Sketch a graph of the equation of y=3x+2

Looking at this equation you can see that it is in the form of y = mx + c and we know that this is the equation of a straight line. One way to solve this would be to inspect the equation and see that the c c...
HB
Answered by Hannah B. • Maths tutor
8331 Views

Rationalise the denominator of the fraction 3/sqrt(5)

In order to rationalise the denominator we need to get rid of the surd (square-root) on the bottom of the fraction. To do this, we can multiply the denominator by sqrt(5). But we must notice that to keep the...
MM
Answered by Murray M. • Maths tutor
20486 Views

Does the function y=x^3+x+(x^2+1)e^x have a horizontal tangent?

We want to determine whether a function has a tangent which is horizontal. To answer the question we need to know what a horizontal tangent to a function means. A tangent to a graph of a function is a line w...
DE
Answered by Daniel E. • Maths tutor
6840 Views

Solve the simultaneous equations: y=5-x and y=x+1.

Since y is equal to both 5-x and to x+1, we know that 5-x is equal to x+1. We can write 5-x=x+1. Take 1 away from each side: 4-x=x. Then add x to each side: 4=2x. Divide both sides by 2: 2=x. Now we have x, ...
CW
Answered by Charlotte W. • Maths tutor
19555 Views