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Solve 5x + 10 = 2x(5x + 10)

First multiply out the right hand side to get5x + 10 = 10x^2 + 20xThen rearrange so everything equals zero, forming a quadratic equation10x^2 + 15x - 10 = 0 To make things easier, you can simplify the equati...
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Answered by Amy M. • Maths tutor
4475 Views

Solve the simultaneous equations 3x + y = –4 and 3x – 4y = 6

Label first equation as equation 1 and the second as equation 22) Make y the subject of the equation from equation (1); hence: eq 1 : y = -4 -3x3) Substitute the new equation into equation (2) : 3x- 4(-4-3x)...
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Answered by Munachi I. • Maths tutor
3435 Views

Solve the simultaneous equations: y = x + 6, x^2 + 2y = 9

y = x + 3x 2 + 2y = 9We want to make the squared equation have either only x's or only y's, so we substitute y = x + 3 into the equation:x 2 + 2(x + 3) = 9We need to take out the brackets, and simplify this ...
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Answered by Hayley H. • Maths tutor
3790 Views

Solve 3x - 5 < 16

When solving inequalities, you should treat them like solving any regular equation that you are used to (ie. whatever operation you perform on the left hand side, you must perform on the right hand side also...
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Answered by Mylan R. • Maths tutor
4912 Views

Factorise a^2 + a - 30

This is a quadratic equation in the form ax 2 +bx+c. As the three terms don't have a common factor we cannot factorise this into one bracket, instead we will factorise it into two. In order to do this we mus...
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Answered by Isabella G. • Maths tutor
5331 Views