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Solve (6x-2)/4 - (3x+3)/3 = (1-x)/3. (4 marks)

(6x-2)/4 - (3x+3)/3 = (1-x)/3 multiply both sides of the equation by 12=lowest common multiple of 4 and 3 3(6x-2) - 4(3x+3) = 4(1-x) expand brackets 18x - 6 -12x - 12 = 4 - 4x simplify 6x - 18 = 4 - 4x10x = ...
EL
Answered by Eleanor L. • Maths tutor
3490 Views

How do I use the quadratic formula?

So far in your learning it is likely that you have been learnt that if you can't factorise a quadratic equation then you can not solve for x. The quadratic formula is overcomes this restriction, allowing you...
OI
Answered by Olumide I. • Maths tutor
3168 Views

Q) The equation of a curve is y=(x+4)^2+7. Find the co-ordinates of the turning point

Full Explanation: We have our Equation: y=(x+4) 2 +7 At the turning points, the gradient, (m) is zero m=0 = dy = 0To work out the gradient, we must differentiate the equation dx The formula to differentiate ...
JC
Answered by Jake C. • Maths tutor
4109 Views

There are 14 boys in a class and 16 girls. The Mean height of the class is 1.6m, the mean of the girls is 1.5m what is the mean height of the boys?

Mean for all students: (the sum of all the heights)/total number of students = (the sum of boys+sum of girls)/30 = 1.6sum of boys and girls = 1.6 x 30Mean for girls: (the sum of all the girls' heights)/total...
CJ
Answered by Caitlin J. • Maths tutor
5062 Views

Solve the two simulatneous equations x^2+y^2=18 and x-y=3

1) X2 +2Y2= 18 2) X - Y = 3 Rearrange 2) in the form X=3-Y then substitute in to 1); (3-y)2 +2Y2=18, this is your new equation 3 9+3Y+3Y+Y2+2Y2=18 3) 9+6y+3Y2= 18 Divide equation 3) by 3 3 +2Y+Y2=6 Solve for...
RC
Answered by Rebecca C. • Maths tutor
6137 Views