Top answers

PQRS is a parallelogram with P->Q=a and P->S=b. Find S->Q in terms of a and b. N is a point between S and Q, where SN:NQ is 3:2, find N->R

Vectors are special in that they have a direction as well as magnitude (size). To get from S->Q you can go from S->P = -b and then P->Q = a so S->Q = - b + a = a - b (remember underlining) To fin...
KB
Answered by Kristian B. • Maths tutor
6153 Views

How can I draw a 30 degree angle without a protractor?

In the exam you will have a ruler and a pair of compasses, which you can use to construct a 60 degree angle by drawing two arcs. You can then draw two more arcs to bisect that 60 degree angle and make a 30 d...
ZC
Answered by Zoe C. • Maths tutor
24640 Views

i) Make y the subject of the expression x = ((a-y)/b))^1/2 ii) Simplify fully (2x^2 − 8)/(4x^2 − 8x)

i) Square both sides of the expression to make x^2=(a-y)/b Multiply by b to remove the fraction from the equation and then rearrange to make y the subject. bx^2=a-y --> y=a-bx^2 ii) First factor out 2 fro...
OS
Answered by Oscar S. • Maths tutor
4845 Views

A semicircle has a diameter of 8cm, what it the area?

Area of a circle = pi × r 2 Area of semi-circle = 1/2(Area of circle) = 1/2(pi × r 2 ) Diameter = 2r r = 8÷2 = 4 Area of semi-circle = 1/2(pi × 4 2 )
AP
Answered by Annabelle P. • Maths tutor
9587 Views

Solve algebraically the simultaneous equations: x^2+y^2 = 25 and y-3x=13

To answer this question, we need to make y the subject of the second equation. We can do this through simple rearrangement: y-3x=13 so y=13+3x Now that we have y on its own, this means we can substitute for ...
JK
Answered by James K. • Maths tutor
8954 Views