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Calculate the relative formula mass of Iron(III) Oxide (Fe2O3)

Iron (III) / Fe3+ Mr = 56Oxygen / O Mr = 16 Iron (III) Oxide formula = Fe2O3 2x Iron (III) = 56 * 2 = 1123x Oxygen = 16 * 3 = 48 48 + 112 = 160 Fe2O3 relative formula mass = 160
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Answered by Rob C. • Chemistry tutor
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This is a question from a past paper: https://prnt.sc/r6jnxc

The answer is in the same image as the question.
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