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Solve the simultaneous equations x^2 + y^2 =13 and x= y - 5.

(y-5) 2 + y 2 = 13y 2 -10y +25 + y 2 =13.2y 2 -10y+12=0.y 2 -5y+6=0.(y-3)(y-2)=0. So, y=3 or y=2. Then substituting these values of y back into x=y-5 gives, x=-2 when y=3 and x=-3 when y=2.
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Answered by Hollie D. Maths tutor
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Das neue Jahr Zu der Party in Berlin sind hunderttausende Menschen gekommen . Es waren so viele, dass die Polizei de n Platz schon früh am Abend geschlossen hat . Um Mitternacht gab es dann ein großes Feuerw...
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Answered by Lauren M. German tutor
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Expand (x+4)(x-4)=33 to give values of x

Use FOIL to expand the brackets. To do this, we start by multiplying the FIRST value in each bracket which in this case is x so we get x^2. Then we multiply the OUTSIDE two values, so here that is x and -4 s...
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Answered by Aria B. Maths tutor
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How do surds relate to powers and roots?

To understand surds we have to understand powers and there uses. So to start we should look at powers such as what is 2 2 , 3 2 , and 5 2 . This shows us going up but then we look at how we square root thing...
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Answered by Alistair G. Maths tutor
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Explain why an athlete loses water when exercising.

The athlete begins to sweat, as exercising releases energy from the body in the form of heat, so the water evaporating from the surface of the skin results in the body cooling down.
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Answered by Joy B. Biology tutor
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