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Solve the following simultaneous equations: 2y+x=8 , 1+y=2x

This is a very common type of question that might be asked in an exam and there are 3 methods we could use to solve this; by substitution, by elimination (or subtraction) or by using straight line graphs. Th...
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Answered by Ben R. • Maths tutor
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Expand and simplify 2y+3y(5y+3)

BIDMAS Following BIDMAS, multiply the bracket out before the addition of the 2y. 3y(5y+3) = 15y 2 +9y adding the 2y gives the calculation of 15y 2 + 9y +2y = 15y 2 + 11y
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Answered by Emma S. • Maths tutor
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Derive the following with respect to x1: y=(x1*x2)/(x1+x2).

y is a function of x 1 and x 2 . We are asked to derive y with respect to x 1 , meaning that x 2 remains constant. Note that y ' is the derivative of y. Both the numerator and denominator of the fraction con...
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Answered by Thaleia K. • Maths tutor
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By using the substitution x = tan(u), find the integral of [1 / (x^2+1) dx] between the limits 1 and 0

First we need to change the limits, and by plugging in 1 and 0 to our substitution we find that the limits for u are arctan(1) and arctan(0) (or pi/4 and 0). Then we need to substitute for dx, and by differe...
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Answered by Ollie W. • Maths tutor
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Solve the equation (2X + 3) / (X-4) - (2X - 8) / (2X + 1) = 1

In order to solve this equation we need to find a common denominator for the 2 fractions. It is impossible to name the common denominator while working with unknown variables such as x,y etc. but we know fro...
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Answered by Octavian G. • Maths tutor
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