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solve the simultaneous equations x^2 + y^2 = 5 and 3x+1=y

Substitute in y to the first equationx 2 + (3x+1) 2 = 510x 2 + 6x - 4 = 55x 2 +3x-2=0(5x-2)(x+1)x=2/5 or -1Sub these values of x into the first equationy=11/5 and -2
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Answered by Isabel D. • Maths tutor
3597 Views

How do I find 28% of 160?

To find more complicated percentages, we need to first be able to convert percentages into fractions. To do this, we take 100 as the denominator and the percentage as the numerator, so 28% = 28/100. Now we c...
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Answered by Aiman K. • Maths tutor
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How do I solve the equation 5y+18=3y+4?

First collect the like terms on one side.(-3y) 2y+18=4Then solve as a normal equation.(-18) 2y=-14(÷2) y=-7
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Answered by Aiman K. • Maths tutor
3445 Views

The area of square ABCD is 10 cm^2 . Show that x^2 + 6x = 1 (requires diagram which I will draw on the whiteboard).

The area of a square is the length of one side squared (multiplied by itself), so for a square with side length 3, the area will be 3 2 or 3 x 3, which = 9. For a square with side length x, the area will be ...
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Answered by Matilda L. • Maths tutor
22170 Views

How do I solve simultaneous equations? Such as 2x + 4y = 8, 3x + 2y = 8.

There are two easy ways to solve simultaneous equations. Substitution and elimination. In order to work with substitution we must rearrange one equation to be equal to either x or y. In this case, 2x+4y=8, c...
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Answered by Cameron T. • Maths tutor
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