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Find dy/dx at t=3, where x=t^3-5t^2+5t and y=2t^2

Using the product rule, we find that dy/dx= dy/dt multiplied by dt/dx, where dt/dx is the reciprocal of dx/dt dx/dt= 3t^2-10t+5, dy/dt= 4t At t=3, dx/dt= 3(3)^2-10(3)+5=2, dy/dt= 4(3)= 12 Therefore, dt/dx= 1...
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Answered by Oore A. • Maths tutor
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A) Multiply out 6(n - 2). B) Factorise psquared - 5p

A) 6n - 12 B) p(p-5)
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Answered by Ally W. • Maths tutor
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Express 21/root7 in the form k root7.

21/root 7 = 21root7/7 = 3root7 k = 3
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Answered by Ally W. • Maths tutor
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Given that y = 5x(3) + 7x + 3, find A) dy/dx B) d2y/dx2

A) 15x 2 +7 B) 30x
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Answered by Ally W. • Maths tutor
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Calculate the equation of a line that passes through the point (2,4) and has a gradient of 1.5 in the form y=mx+c

y-y1=m(x-x1) y-4=1.5(x-2) y-4=1.5x-3 y=1.5x+1
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Answered by Katie H. • Maths tutor
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