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A particle P moves with acceleration (-3i + 12j) m/s^2. Initially the velocity of P is 4i m/s. (a) Find the velocity of P at time t seconds. (b) Find the speed of P when t = 0.5

Solution: V = V (0) + a *t From the question: a = (-3 i + 12 j ); V (0) = 4 i V at time t seconds: V = 4 i + (-3 i +12 j )*t V = 4 i + (-3t i + 12t j ) V = 4 i – 3t i + 12 t j m/s *Bold letters are vectors A...
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Answered by Artur R. • Maths tutor
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Using the quadratics formula find the two solutions to x^2 + 3x + 2 = 0.

x 1 = (-b + (b 2 - 4ac) 1/2 )/2a and x 2 = (-b - (b 2 - 4ac) 1/2 )/2a. So with the values a = 1, b = 3 and c = 2: x 1 = (-3 + (3 2 - 8) 1/2 )/2 and x 2 = (-3 - (3 2 - 8) 1/2 )/2, x 1 = (-3 + 1)/2 = -1 and x ...
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Answered by Rebecca D. • Maths tutor
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Starting with x^2+2x+1=0 use the method of factorising to solve for x.

x 2 +2x+1=0, (x+1)(x+1)=0, (x+1) 2 =0. So x=-1
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Answered by Rebecca D. • Maths tutor
4417 Views

How do you differentiate a function?

The differential of a function is defined by the expression: dy/dx = Lim(dx->0) of (f(x+dx)-f(x))/dx. For functions only involving powers of x, the differentioal can easily be calculated by timesing by th...
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Answered by Max H. • Maths tutor
4123 Views

Line AB, with equation: 3x + 2y - 1 = 0, intersects line CD, with equation 4x - 6y -10 = 0. Find the point, P, where the two lines intersect.

Let eqn. 1 be: 3x + 2y - 1 = 0 & Let eqn. 2 be: 4x - 6y -10 = 0 Multiply eqn. 1 by a factor of 3, and add the two eqautions together. (This eliminates y from the equation) This gives: 9x + 6y - 3 = 0 + 4...
KS
Answered by Kris S. • Maths tutor
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