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Solve (4-2x)/(x+1)=x

To solve this equation, we need to collect all of the x^2 terms and the x terms together. To do this we should start by getting rid of the fraction on the left-hand side by multiplying both sides by the deno...
EK
Answered by Emily K. • Maths tutor
10311 Views

A* grade question: ((2x+3)/(x-4))-((2x-8)/(2x+1))=1 solve for X

Multiply whole equation by x-4 and then 2x+1 (would do this one step at a time but must conserve space here): (2x+3)(2x+1)-(2x-8)(x-4)=(x-4)(2x+1) Expand brackets: (4x^2+8x+3)-(2x^2-16x+32)= 2x^2-7x-4 Do the...
BL
Answered by Becky L. • Maths tutor
4829 Views

solve the following equation: x^2 - 7x -15 = 3

Rearrange the equation so x^2 - 7x -18 = 0, then simplify into (x-9)(x+2)=0 -> x=9 or x=-2
JS
Answered by James S. • Maths tutor
3276 Views

State the trigonometric identities for sin2x, cos2x and tan2x

sin2x = 2sinxcosx cos2x = cos^2(x) - sin^2(x) tan2x = (2tanx)/(1-tan^2(x))
JS
Answered by James S. • Maths tutor
21141 Views

Expand and Simplify: 2y(3x - 8) + x(2x + y)

Start by expanding the brackets. This means that you must multiply everything inside the bracket by whatever is outside the bracket. Therefore, you should be left with: 6yx - 16y + 2x^2 + xy After this, you ...
JB
Answered by Jasmine B. • Maths tutor
4608 Views