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Line L1 passes through points (4,6) and (12,2). Line L2 passes through the origin and has gradient -3. The two lines intersect at point P. Find the co-ordinates of P.

Gradient of L1 : Gradient = Change in y/ Change in x. Gradient = (2-6)/(12-4)= -1/2 Gradient is "m" in y=mx+cPlug in a point to determine c : 6 = -1/2 *4 + c --> c =8 L1 is given by y=-1/2x +8 L...
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Answered by Bjorn L. • Maths tutor
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Using the quadratic formula find the solutions for x^2+x-6

By subbing in a=1 b=1 and c=-6 into the quadratic formula, you should get two solutions of x which are x = 2 and x = -3
LO
Answered by Loretta O. • Maths tutor
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Write x^2 + 4x - 16 in the form (x+a)^2-b

Concentrate on the x^2+4x. Halve the 4 or any number that occupies that space. Equals 2 in this case. Put (x+2)^2 and that is your first term. Expand the brackets= x^2 + 4x + 4. Don't want the extra + 4 as t...
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Answered by Lucy B. • Maths tutor
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a=7 and b=2, Work out the value of (a/b)-a^b

(7/2) - 7 2 (7/2) - (98/2)= -(91/2)
LP
Answered by Lauren P. • Maths tutor
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A curve has the equation y=3x^3 - 7x^2+52. Find the area under the curve between x=2 and the y-axis.

With a question like this. Firstly you have to read it, of course. But more importantly you have to understand what it is asking of you. So it is asking to find the area with boundaries at x=2 and the y axis...
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Answered by Calvin C. • Maths tutor
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