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(2x + 3)/(x-4) - (2x - 8)/(2x + 1) = 1

Multiply through by both denominators, giving us the equation (2x + 3)(2x + 1) - (2x - 8)(x - 4) = (x-4)(2x +1). If we expand the brackets, we arrive at 4x^2 + 8x + 3 - (2x^2 -16x + 32) = 2x^2 -7x -4. If we ...
HR
Answered by Harry R. • Maths tutor
4359 Views

Solve the simultaneous equations: 3a + 2b = 17 and 4a - b = 30

Here we have a pair of simultaneous equations with two unknowns. There are two methods of going about this question: substitution or elimination. Today, we shall be focusing on the latter. We need a pair of ...
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Answered by Yashna R. • Maths tutor
13378 Views

Factorise x^2+7x+10 to find the roots of the equatino x^2+7x+10=0

When we are asked to solve a quadratic, we can use the formula, but we are here specifically asked to use factorisation. First of all, we need to know the format of factorisation: usually, it's (x+ )(x+ ), a...
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Answered by Felix H. • Maths tutor
7506 Views

Find dy/dx when y = 2ln(2e-x)

Answering this question requires knowledge of e and ln. If we look at the question we can see 2 is being multiplied by the ln, so we might want to use the product rule. Also, we can see that the ln has a big...
JL
Answered by Jay L. • Maths tutor
10314 Views

Expand and simplify (x+12)(x-3)

In order to solve this question, I am going to use the FOIL (first, outer, inner, last) method of expanding brackets. First we need to multiply the two first elements in each bracket together - in this case ...
JL
Answered by Jay L. • Maths tutor
12610 Views