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How do you differentiate (2x+xe^6x)/(9x-(2x^2)-ln(x)) w.r.t. x?

This problem requires using the quotient rule, product rule and the chain rule. The derivative of the entire thing is ((du/dx)v-(dv/dx)u)/v^2 where u=2x+xe^6x and v=9x-2x^2-lnx. dv/dx is relatively straitfor...
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Answered by Seth H. • Maths tutor
3728 Views

Solve for X and Y: 2y + x = 7; 3y - x = 8

x=1, y=3; Firstly, rearranging for x in the first equation: x = (7-2y); Substitute this into the second equation: 3y - (7 -2y) = 8; Expand: 3y -7 +2y = 8 (watch negative) 3y +2y = 15 Therefore, 5y = 15 and y...
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Answered by Ruth K. • Maths tutor
5782 Views

A right-angled triangle has side lengths of 8.65cm and 10.15cm. What is the length of its hypotenuse?

Step 1: Draw a labelled diagram of the triangle, marking the side lengths. Step 2: Recall Pythagoras’ theorem equation ‘c2=a2+b2’ Step 3: Substitute the values of a and b into the equation. c2=8.652+10.152 S...
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Answered by Alisha M. • Maths tutor
3942 Views

What is the best way to revise for my Maths GCSE?

I believe that there is no better way to revise for Maths than to continually practice questions (especially those that you find most tricky!) The more you practise, the easier you'll find the questions beca...
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Answered by Alisha M. • Maths tutor
4267 Views

How do I solve this pair of simultaneous equations: 3x+y=7 and 3x-y=5?

Step 1: Eliminate the ‘y’ component from the equations by adding the equations together. This gives the new equation ‘6x=12’ Step 2: Find the value of x by dividing both sides of the equation by 6. This give...
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Answered by Alisha M. • Maths tutor
4936 Views