Top answers


A circle with centre C has equation x^2 + y^2 + 2x - 6y - 40 = 0. Express as (x - a)^2 + (y - b)^2 = d.

First we must complete the square on both x and y. To complete a square we must take the number before the x and half it, for example nx we get n/2. We then write it as (x + n/2) 2 - (n/2) 2 . So for our que...
RM
Answered by Reuben M. Maths tutor
8768 Views

The following sequence reads: 8, 5, 2, -1. What are the 4th and 50th terms of this sequence?

With sequences we should follow the general formula of An + B . The n refers to the position in the sequence i.e. for the 3rd number in the sequence (which is 2 in the above sequence) n=3. The A refers to th...
AS
Answered by Aneesh S. Maths tutor
6225 Views

Arrange the following decimals in order of size: 0.45, 1.09, 0.3, 0.08

There are 5 steps you can follow to make this sort of problem easier to handle: 1) Line up all of the values in a column with the decimal points under each other 2) Ensure each value is the same length by fi...
AS
Answered by Aneesh S. Maths tutor
8744 Views

Using Pythagoras Theorem find the length of the hypotenuse of a right triangle where a=7 cm and b=11 cm. Round to the nearest tenth

Pythagos Theorem states that a^2 + b^2 = c^2 So using the figures we are given the equation would look like this: 7^2 + 11^2 = c^2 We square the numbers we can and then get: 49 + 121 = c^2 We add the left ha...
MB
Answered by Mary B. Maths tutor
6003 Views

Using Trigonometric Identities prove that [(tan^2x)(cosecx)]/sinx=sec^2x

You should begin by identifying all the Trigonometric Identities that may be useful in this problem. Specifically, cosecx=1/sinx tanx=sinx/cosx 1/cosx=secx and possibly tan^2x + 1= sec^2x. I began by changin...
MB
Answered by Mary B. Maths tutor
9923 Views