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Find Solution to x^2 + x - 2=0

Using the factorisation method. the factorised solution will look like (x+a)(x+b) = 0 by multiplying these two brackets we get the equation: x^2 + a.x+b.x + a.b = 0 so vomparing this to the equation in the q...
MP
Answered by Matthew P. • Maths tutor
5910 Views

How do you factorise fully 3 a^3 b + 12 a^2 b^2 + 9 a^5 b^3?

WORKING OUT 3a 3 b+12a 2 b 2 +9a 5 b 3 1) 3(a 3 b+4a 2 b 2 +3a 5 b 3 ) 2) 3a 2 (ab+4b 2 +3a 3 b 3 ) 3) Fully factorised: 3a 2 b(a+4b+3a 3 b 2 ) BRIEFLY EXPLAINED Factorising is the process of taking out any ...
AW
Answered by Anna W. • Maths tutor
4784 Views

How can I improve my score?

Maths is all about practise. Once you have covered a topic, you should do as many practise questions as possible to help you understand the topic. Always show your working out on your exam paper to gain maxi...
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Answered by Samah L. • Maths tutor
4975 Views

The curve C has the equation y = 2x^2 -11x + 13. Find the equation of the tangent to C at the point P (2, -1).

The first step is to differentiate the equation of the curve in order to find the gradient of the tangent at the curve. Remember that when differentiating polynomials, we multiply the index of the variable x...
JY
Answered by James Y. • Maths tutor
17694 Views

A curve has the equation (x+y)^2 = xy^2. Find the gradient of the curve at the point where x=1

The first step is to find dy/dx. To do this you must first expand the brackets. x 2 + y 2 + 2xy = xy 2 Then differentiate each term with respect to x. dy/dx of (x 2 ) = 2x dy/dx of (y 2 ) = 2y(dy/dx) (Using ...
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Answered by Motunrayo O. • Maths tutor
18026 Views