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Solve the simultaneous equations: 5x + y = 21, x - 3y = 9

5x + y = 21x - 3y = 9First, find the lowest common multiple for x or y and make the equations equal for either x or y.Here, we multiply the second equation by 5 to make the amount of x the same. The equation...
SP
Answered by Sophia P. • Maths tutor
4634 Views

Given that f(x ) = 4x^3 + 12, evaluate f ( −2) .

In this question we are looking to find a value by substitution. In this case we are substituting the integer (-2) into the equation in place of the x which would be illustrated as f(-2)= 4(-2)^3+12. It is i...
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Answered by Mikele P. • Maths tutor
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Solve x^3+2*x^2-5*x-6=0

First find a root of the function: f(x)=x^3+2x^2-5x-6 f(2)=(2)^3+2*(2)^2-5*(2)-6 =0. Therefore, (x-2)(x^2+Ax+3)=0 where A is an unkown constant. Compare x^2 coeffecients: A-2=2, A=4. So (x-2)(x^2+4x+3)=0. Th...
Answered by • Maths tutor
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A new sports car accelerates using rockets at 5m/s for 30 seconds from some traffic lights and then decelerate for 45 seconds to a stop.

SUVAT Part (A) Part (B) S=? S=?U=0 U= Calc From A (V)V=? V= 0T=30s t=45sPart A: V=U+atV=0+5 30V= 150S=ut+at 2 S=0+5 30*30S=4500mPart B: S=(U+V) t/2S=75 45S=3375mTotal Distance = 3375+4500=7875
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Answered by Matthew W. • Maths tutor
3300 Views

A game consists of 5 cups turned upside down, under one of the cups is a prize. 5 friend's pick a cup in turn and lifts it up, if they get the prize, they win , but if not, the cup is removed and the next friend picks. What position is it best to pick?

The first friend to choose has 5 cups to pick from and only 1 that will win them the prize, so their probability of winning is 1/5.The 2nd friend relies on the first friend to not win, this with a probabilit...
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Answered by Alex M. • Maths tutor
2730 Views