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How do I find the co-ordinates of a stationary point of a given line and determine whether it is a minimum or a maximum point?

When you find the first derivative of the equation and equate it to 0 then solve for x, you will find the x-coordinates of the stationary point(s) of the graph. For example, let's say f(x)=-x 3 +x 2 +8x+10 t...
Answered by • Maths tutor
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Work out 2^14 ÷ (2^9)^2 in its simplest form

2 14 ÷ (2 9 ) 2 I would start with the second part of this equation as that looks like it needs simplifying. When 'powers of' are in brackets to each other, they are multipled i.e. (2 9 ) 2 = 2 9x2 = 2 18 . ...
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Answered by Sion D. • Maths tutor
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How do you find the first order derivative of sin(x) and cos(x) functions?

The general rules are:d(sin x)/ dx = cos xd(cos x)/ dx = -sinxHowever, if you have a constant k in the function such as y = sin(kx), the derivative will be dy/dx = kcos(kx). (For y = cos(kx), the derivative ...
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Answered by Niusha S. • Maths tutor
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Find the x-coordinates of any stationary points of the equation y = x^3 - 2x + 4/x

y = x^3 - 2x +4/x, dy/dx = 3x^2 - 2 - 4/(x^2) = 0 at the stationary points, 3x^4 - 2x^2 - 4 = 0, substitute in u for x^2: 3u^2 - 2u - 4 = 0, use the quadratic formula: u = (-(-2) +- sqrt((-2)^2 - 4 3 (-4)))/...
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60 students were taking a Maths, Physics or Chemistry exam. 38 of the students were male. 11 of the 32 students who were taking the Maths exam were female. 8 males were taking the Physics exam. 12 students were taking the Chemistry exam. One of the fe

60-38 = 22 females 32+12=44 students taking the Chemistry and Maths exam. Therefore 60-44=16 students were doing the Physics exam, so 16-8= 8 females were taking the Physics exam. This means that 22-11-8 =3 ...
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Answered by Harry B. • Maths tutor
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