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Solve the simultaneous equation, 3x + y = 8 and x + 3y = 12, to find a value for x and y.

Re arrange one of the equation to get a single variant answer. So, x = 12 - 3y. Substitute this into the other equation, so 3 (12-3y) + y = 8. Expand this equation to form 36 - 9y + y = 8. Collect the y term...
GR
Answered by Grace R. • Maths tutor
7139 Views

Show that (x + 4)(x + 5)(x + 6) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.

=(x+4)(x 2 +6x+5x+30)=(x+4)(x 2 +11x+30)=x 3 +11x 2 +30x+4x 2 +44x+120=x 3 +15x 2 +74x+120
JZ
Answered by Jiawen Z. • Maths tutor
3276 Views

Solve for x and y using these simultaneous equations: 2x + 3y = 21, y = 2x - 1

Substitute y = 2x - 1 into the first equation. 2x + 3(2x -1) = 21 2x + 6x - 3 = 21 8x = 24 x = 3 Therefore y = 2(3) - 1 = 5
AL
Answered by Alexandra L. • Maths tutor
3343 Views

factorise x^3 + 3x^2 - 13x - 15

For convience we can call the polynomial f(x). Using the fact that the product of the roots of a polynomial equals the constant term, we know that the product of the roots is -15. We can therefore guess a ro...
BI
Answered by Ben I. • Maths tutor
7102 Views

The Diagram shows the Triangle PQR. PQ = x cm. PR = 2x cm. Angle QP^R = 30 degrees. The area of the triangle PQR = A cm^2. Show that x = (Squared Root){2A

Area of a Triangle Formula is A = 1/2 abSINc Label the sides of the triangle PR = 2x = a PQ = x = b 1/2 (x) 2x (x) x (x) SINc = A = x 2 SINc Rearrange the equation to give (squared root) { A = x { SINc QP^R ...
TD
Answered by Tutor305386 D. • Maths tutor
11840 Views