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Solve algebraically the simultaneous equations x^2 + y^2 = 25 and y - x = 1

Let's label the equations x 2 + y 2 = 25 (1) y - x = 1 (2). We can use substitution to solve this simultaneous equation. Let's make y the subject of the equation (2) and we get y = x + 1. Now, lets find y 2 ...
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Answered by Vithya N. Maths tutor
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Rationalise the surd: 2/root(x)

To rationalise a surd means to manipulate a fraction involving terms which are being square rooted so that no term in the denominator is being square rooted. For this example 2/root(x) we multiply the fracti...
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Answered by Daniel T. Maths tutor
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Solve 3x^2+7x-13=7 to find x.

Firstly, you need to get the equation to equal zero, so that you can use the quadratic formula to solve. Therefore you subtract 7 from both sides, meaning the equation becomes: 3x^2+7x-20=0. Recall the quadr...
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Answered by Ellie M. Maths tutor
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Solve (6x-2)/4 - (3x+3)/3 = (1-x)/3. (4 marks)

(6x-2)/4 - (3x+3)/3 = (1-x)/3 multiply both sides of the equation by 12=lowest common multiple of 4 and 3 3(6x-2) - 4(3x+3) = 4(1-x) expand brackets 18x - 6 -12x - 12 = 4 - 4x simplify 6x - 18 = 4 - 4x10x = ...
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Answered by Eleanor L. Maths tutor
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How do I use the quadratic formula?

So far in your learning it is likely that you have been learnt that if you can't factorise a quadratic equation then you can not solve for x. The quadratic formula is overcomes this restriction, allowing you...
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Answered by Olumide I. Maths tutor
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