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Let f(x)= x/5 + 1 . Find f^-1(x)

f^-1(x)= 5(x-1)
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Answered by Ella C. • Maths tutor
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Make x the subject of the formula y = x/3 -2a

y =x/3 - 2a y + 2a = x/3 3y+6a = x
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Answered by Ella C. • Maths tutor
9413 Views

How do we integrate a quadratic equation?

Increase the power by one and divide by the new powere.g. integrate x 2 +5x + 3Answer: x 3 /3 + 5x 2 /2 + 3x
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Answered by Sophia P. • Maths tutor
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dy/dx= 2x/2 - 1/4x, what is d2y/dx2?

(2x)/2= 2x^-2d2y/dx2= -4x^-1 - 1/4
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Answered by Gloria N. • Maths tutor
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Find ∫(2x^5 -4x^-3 +5) dx

So we have to integrate these 3 terms one by one. To integrate 2x 5 you add 1 to the power of x, so that becomes 6, you then divide the coefficient by the new power of x. So 3/6=1/2 giving the integral of 2x...
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Answered by Peter S. • Maths tutor
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