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Expand and simplify (x − 4)(2x + 3y)^2

Rewrite (x − 4)(2x + 3y) 2 as (x - 4)(2x + 3y)(2x + 3y) Multiply out the first two brackets to give -(2x 2 + 3xy - 8x 2 - 12y)(2x + 3y) Multiply out the remaining brackets4x 3 + 6x 2 y - 16x 2 - 24xy + 24xy ...
HK
Answered by Henry K. • Maths tutor
16687 Views

Find the values of x and y when 3x+4y=18 and 4x+2y=14

Label equations: (a) 3x+4y=18(b) 4x+2y=14We need to be able to cancel out either the x's or the y's. The simplest choice is to double (b) so that we can cancel out the y's.2 x (b) : 8x+4y=28 (Give this a new...
RE
Answered by Rosie E. • Maths tutor
6478 Views

Solve the simultaneous equations 3x + 2y = 12 and 10y = 7x + 16

First we need to rearrange both equations into the form ax + by = c (where a, b and c are the integers). We can label these 1. and 2.We then have:3x + 2y = 12 1.7x -10y = -16 2.In order to find the x value, ...
AA
Answered by Anjali A. • Maths tutor
4614 Views

Rewrite (2+(12)^(1/2))/(2+3^(1/2)) in the form a+b((c)^(1/2))

To solve:Rewrite the top part of the fraction to get it in terms of 3^(1/2)Rationalise the denominatorSimplify The final answer is 2(3^(1/2)) - 2
MM
Answered by Max M. • Maths tutor
3978 Views

The width of a rectangle is X cm.
 The length is 1·5 cm more than the width.
 The perimeter of the rectangle is 17 cm. Write down an equation satisfied by X
 and solve it to find X.

Let's call the length ' L ', and the width ' X '. Since the length is 1.5cm more than width, we can form the equation: L = X + 1.5 (Equation 1)Let's call the perimeter ' P '. Therefore, we know that P = 17cm...
OD
Answered by Oliver D. • Maths tutor
7840 Views