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A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.

Vertically: u=0 ms -1 s=1.2 m a=9.8 ms -2 s=ut + 0.5at 2 Therefore t = 0.49s Horizontally: t=0.49s s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms -1
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Answered by William W. • Physics tutor
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What is the life cycle of a star?

Star formation begins when dust and gas starts to gather to form a cloud called nebula . Gravity causes the cloud to spiral and form a Protostar , where gravity accelerates the gas particles, resulting in he...
BP
Answered by Barbara P. • Physics tutor
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If photons are little particles emitted by atoms, where were they before they got emitted?

Eisntein showed that in his theory of relativity that energy and mass were no longer conserved, as they are in Newton's theory. This completely changes how we see particles. They are no longer fundamental bu...
US
Answered by Uther S. • Physics tutor
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How would you prove the formula for the total capacitance of a system consisting of several capacitors linked in series?

The first thing you need to do is to decide what is kept constant within the system. (P.S. Essentially all problems in physics require conservation laws to some extent) In the case of components in series, y...
VG
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What provides the centripetal force on a satellite and what are the factors that determine the size of the centripetal force on the satellite

Centripetal Force = (mv^2)/r The centripetal force must always act towards the centre of the circle in which the satellite is travelling. Therefore it is a attractive force from the Earth and hence gravitati...
NH
Answered by Namita H. • Physics tutor
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