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Base Case n=1sum_1(r 3^(r-1))=1 3^0=1=1/4+(3^1/4) (2-1)=1/4+3/4=1 Assume true for n=ki.e. sum_k(r 3^(r-1))=(3^k/4) (2k-1) then for n=k+1sum_(k+1)(r 3^(r-1))= sum_k(r 3^(r-1))+(k+1) 3^k =(3^k/4) (2k-1)+(k+1) ...

Similarities: - Both consist of a pentose sugar , a phosphate group and 4 nitrogenous bases. - Both are joined by covalent phosphodiester bonds between the phosphate and pentose sugar groups. Differences: - ...

NB this question is discussion based and could be approached from many different angles and include more ideas than I have covered below. I have split this question into 2 parts. Firstly you could dress why ...

-There are a large number of alveoli , increasing the surface area available for gas exchange. The alveoli have many infoldings , further increasing the surface area. - The walls of the alveoli are thin , th...

One major controversy regarding economic globalisation is that it results in the perpetuation of economic inequalities between states due to the need for developing states to enter the global free market. Th...