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A car costs £10,000 and it has a depreciation policy of 15% each year, reducing balance method. what is the net present value at the end of year 3?

Year 1 £10,000 * 15% = £1,500 (Depreciation for year 1)£10,000 - £1,500 = £8,500 (Net present value at the end of year 1) Year 2 £8,500 * 15% = £1,275 (Depreciation for year 2)£8,500 - £1,275 = £7,225 (Net p...
Answered by • Accounting tutor
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Solve the curve xy=2 and x+y=3

This question is a simultaneous equation, this means we substitute one value into the other equation.We are looking for the points where the curves intersect.First I would take x+y=3 and bring the y over to ...
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Answered by Peter M. • Maths tutor
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What is the value of an investment of £4500 with compound interest of 1.3% after six years?

We solve this by multiplying the starting value, £4500 , by 1 + {the interest rate expressed as a decimal} , or in this case, 1 + 0.013 . This gives us £4500 x 1.013 6 and when we type this into our calculat...
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Answered by Mark C. • Maths tutor
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Describe the process of saprophytic nutrition in soil microorganisms

Enzymes are secreted by the microorganisms and extracellular digestion takes place as the enzymes break down any complimentary substrate. Next, the products of this digestion are absorbed into the microorgan...
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Answered by Mark C. • Biology tutor
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Describe the bonding present in a piece of sodium metal.

A lattice of positive sodium ions with a sea of delocalised electrons distributed around them. The metallic bond consists of the electrostatic force of attracion between the positively charged sodium atoms a...
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Answered by Mark C. • Chemistry tutor
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