Solve the following equation: x^(3) - 6x^(2) + 11x - 6 = 0
x 3 - 6x 2 + 11x - 6 = 0 Let (x-a)(x-b)(x-c) = x 3 - 6x 2 + 11x - 6=> abc = -6 and a + b + c = -6 From abc=-6, find the possibilities of their values: (1,2,-3), (1,-2,3), (-1,2,3), (-1,-2,-3), (1,1,-6), (...