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Solve the simultaneous equations x^2 + y^2 =13 and x= y - 5.

(y-5) 2 + y 2 = 13y 2 -10y +25 + y 2 =13.2y 2 -10y+12=0.y 2 -5y+6=0.(y-3)(y-2)=0. So, y=3 or y=2. Then substituting these values of y back into x=y-5 gives, x=-2 when y=3 and x=-3 when y=2.
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Answered by Hollie D. • Maths tutor
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