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Potassium Chlorate(VII) decomposes to produce Potassium Chloride and Oxygen. Using the following data calculate the enthalpy change of this decomposition: Enthalpy of formation(KClO4) = -430 kJ mol-1, Enthalpy of formation(KCl) = -440 kJ mol-1

Firstly the equation of this decomposition should be worked out to be the following KClO 4 (s) --> KCl(s) + 2O 2 (g) The enthalpy of formation has been given for both KClO 4 and KCl, so from this we know ...
Answered by • Chemistry tutor
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Let N be an integer not divisible by 3. Prove N^2 = 3a + 1, where a is an integer

For N to be not divisible by 3, N can either be of the form 3k + 1 (1,4...) or 3k + 2 (2,5...), where k is an integer. The proof can then be done by checking both 3k + 1 and 3k + 2 when N is squared, to see ...
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What should I include in a personal statement?

When writing your personal statement it can be tempting to include everything you have ever done and all the books you have read. However, due to the restricted length it is important to that you carefully c...
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How can the concept of opportunity cost be explained on different aspects of the economy?

Opportunity cost is the next best alternative choice that someone has. In an economy, it can be confronted by several actors; the government itself, consumers, or firms. On an individual level (consumer) , i...
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Answered by Stavria K. • Economics tutor
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how might a competitive inhibitor prevent the enzyme trypsin from working

inhibitor is a similar shape to the substrate this means the inhibitor blocks the active site of the enzyme the substrate cannot bind to the active site, so fewer enzyme substrate complexes can form
Answered by • Biology tutor
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