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How do you find the normal to a curve at a given co-ordinate?

You first find the gradient of the tangent to the curve at this given co-ordinate by differentiating the given equation of the curve, and then, assuming the equation of the curve is in terms of x, replacing ...
SI
Answered by Srabon I. • Maths tutor
5212 Views

Find the equation of the line that is perpendicular to the line 3x+5y=7 and passes through point (-2,-3) in the form px+qy+r=0

Gradient of line 3x+5y=7: 5y=-3x+7, y=-3/5x+7/5 gradient = -3/5 Gradient of perpendicular line: 5/3 Perpendicular line with points: y+3=5/3(x+2), 3y+9=5(x+2), 3y+9=5x+10, 5x-3y+1=0
PI
Answered by Paul I. • Maths tutor
9541 Views

Differentiate y=sin(x)*x^2.

Using the chain rule, we let u = sin(x) and v = x^2. Then dy/dx = u dv/dx + v du/dx. dv/dx = 2x and du/dx = cos(x). So dy/dx = sin(x) 2x + x^2 cos(x).
LM
Answered by Lucy M. • Maths tutor
4794 Views

Expand and simplify (5a-2b)(3a-4b)

=(5a x 3a) + (5a x -4b) + (3a x -2b) + (-2b x -4b) =15a^2 - 20ab - 6ab + 8b^2 =15a^2 - 26ab + 8b^2
PI
Answered by Paul I. • Maths tutor
11255 Views

Compare the wavelength, frequency and speed of an emitted and reflected microwave

A reflected microwave will have a decreased wavelength, increased frequency and same speed when compared to an emitted microwave.
PI
Answered by Paul I. • Physics tutor
4988 Views