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How can I prepare for the LNAT multiple choice?

The LNAT is supposedly a test that you 'can't' prepare for. It is designed to test your natural aptitude for textual comprehension and structuring arguments - crucial skills for being a lawyer. However, ther...
ZR
Answered by Zara R. • LNAT tutor
3770 Views

Acid HA has a Ka of 2.00 x 10-4mol dm-3. A solution was made by adding 15cm3 of 0.34 M NaOH to 25cm3 of 0.45M HA. Calculate the moles and the concentration of A- and HA in this solution. Using the expression for Ka calculate the pH of the solution

Write the equation : NaOH + HA --> NaA + H 2 O. Find the moles of A - : the moles of A - = the moles of NaOH added. 15 x 10 -3 x 0.34= 5.10 x 10 -3 . Workout the initial moles of HA : 25 x 10 -3 x 0.45= 0...
HS
Answered by Hibba S. • Chemistry tutor
7557 Views

How do I even start going about learning the verb conjugations when there are so many different moods, tenses and endings?

When I was tutoring GCSE students at my school, this was often the first question I was asked. To a GCSE student, the prospect of learning a vast array of conjugation tables seems daunting and verbs tend to ...
DC
Answered by Daniel C. • French tutor
2582 Views

How would you calculate the vertical and horizontal components of the velocity of an object with an initial velocity of 15m/s which is travelling upwards at an angle of 30 degrees to the horizontal?

With these sort of questions involving components, I would always advise drawing a diagram of the problem so that you're clear of the situation!In this case we have an object that is travelling at a speed of...
JP
Answered by Joseph P. • Physics tutor
7554 Views

If a train leaves for a 130 mile journey at 1.30pm, and travels at a constant speed of 50 miles per hour, at what time will it arrive?

First, calculate the time taken for the train to complete its journey: Distance = 130, Speed = 50, Time = Distance/Speed = 130/50 = 2.6 hours. Next, use this to calculate the time of arrival: 2.6 hours = 2 h...
LD
Answered by Luke D. • Maths tutor
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