differentiate 4x^3 + 3x

12x^2 +3

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A function f is defined by f(x) = x^3 - 3x^2 + 1. i) Write down f'(x). ii) Hence find the co-ordinates of the stationary points of the curve y=f(x).


Given that the graph f(x) passes through the point (2,3) and that f'(x)=6x^2-14x+3, find f(x).


How do I integrate 3^x?


A curve has equation 3x^4/3-16y^3/4=32. By differentiating implicitly find dy/dx in terms of x and y. Hence find the gradient of the curve at the point (8,1).


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