What is the gradient of the line passing through the point (1,2) and (5,5)? What is the equation of this line? What is the equation of the line perpendicular to this line that passes through the origin (0,0)?

Gradient of initial line = 3/4 Equation of initial line : y= 3/4x + 5/4 (4y = 3x + 5) Equation of perpendicular line : y= -4/3x 

TA
Answered by Temilola A. Maths tutor

3690 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Fully simplify the expression: 4 / (sqrt(8) + 4)


If x>2y and 2x<5y, what is the range of x when y=6?


Solve the simultaneous equations: 2x+y=18 and x-y=6


Work out (2^34) / (2^3)^10


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences