Solve the following simultaneous equations: (1) 4x+y=7 and (2) 3x+2y=9

This question can be answered by the elimination method. I will choose to eliminate 'y' in this case. Firstly, multiply equation (1) by 2, resulting in 8x+2y=14. Now we can subtract eqaution (2): 3x+2y=9 from equation (1): 8x+2y=14. This results in 5x=5, showing we have eliminated 'y'. Both sides of the equation can be divided by 5. giving x=1. Next, substitute x=1 into equation (1): 41+y=7, so y=3. This means the answer is x=1 and y=3. To check our answer is correct, substitute these values for x and y into equation (2): 31+2*3=9, which gives 9=9 showing us that our answer is correct.

AD
Answered by Alex D. Maths tutor

5560 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is solution by substitution?


The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a.


A shopkeeper compares the income from sales of a laptop in March and in April. The price in April was 1/5 more than in March. The number sold in April was 1/4 less than in March. By what fraction does income decrease from March to April?


y is inversely proportional to d^2. When d = 10, y = 4. d is directly proportional to x^2. When x = 2, d = 24. Find a formula for y in terms of x. Give your answer in its simplest form.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning