Solve the following simultaneous equations: (1) 4x+y=7 and (2) 3x+2y=9

This question can be answered by the elimination method. I will choose to eliminate 'y' in this case. Firstly, multiply equation (1) by 2, resulting in 8x+2y=14. Now we can subtract eqaution (2): 3x+2y=9 from equation (1): 8x+2y=14. This results in 5x=5, showing we have eliminated 'y'. Both sides of the equation can be divided by 5. giving x=1. Next, substitute x=1 into equation (1): 41+y=7, so y=3. This means the answer is x=1 and y=3. To check our answer is correct, substitute these values for x and y into equation (2): 31+2*3=9, which gives 9=9 showing us that our answer is correct.

AD
Answered by Alex D. Maths tutor

5218 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Vectors


f(x) = (2x+3)/(x-4). Work out f^-1 (x)


How do function transformations work?


The first three terms of a sequence are a, b, c. The term-to-term rule of the sequence is 'Multiply by 2 and subtract 4'. Show that c = 4(a – 3).


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences