Solve the following simultaneous equations: (1) 4x+y=7 and (2) 3x+2y=9

This question can be answered by the elimination method. I will choose to eliminate 'y' in this case. Firstly, multiply equation (1) by 2, resulting in 8x+2y=14. Now we can subtract eqaution (2): 3x+2y=9 from equation (1): 8x+2y=14. This results in 5x=5, showing we have eliminated 'y'. Both sides of the equation can be divided by 5. giving x=1. Next, substitute x=1 into equation (1): 41+y=7, so y=3. This means the answer is x=1 and y=3. To check our answer is correct, substitute these values for x and y into equation (2): 31+2*3=9, which gives 9=9 showing us that our answer is correct.

AD
Answered by Alex D. Maths tutor

5645 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express x^2 +10x -3 in the form (x + p)^2 + q


How would you solve the simultaneous equations 2x + y = 7 and 3x - y = 8


Solve x^2 = 4(x - 3)^2


A rectangle has a total perimeter of 32cm with sides of length '3x' and 'x+8'. Solve for x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning