Find the stationary point of 3x^2+7x
dy/dx=6x+7
6x+7=0
x=-7/6
Sub back into original equation; y=98/6
HS
Answered by Harrie S. • Further Mathematics tutor
3198 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸A curve is mapped by the equation y = 3x^3 + ax^2 + bx, where a is a constant. The value of dy/dx at x = 2 is double that of dy/dx at x = 1. A turning point occurs when x = -1. Find the values of a and b.
How would you differentiate x^x?
3x^3 -2x^2-147x+98=(ax-c)(bx+d)(bx-d). Find a, b, c, d if a, b, c, d are positive integers
Prove that sin(x)^2 - 5cos(x)^2 = 6sin(x)^2 - 5