To differentiate a simple equation: y= 4x^3 + 7x

y = 4x^3 + 7 x

Recall: to differentiate any function of the form y = x^n

dy/dx = y' = n x^(n-1)

Hence if y = 4x^3 + 7x

dy/dx = 4 ( 3x^3 -1) + 7x^(1-1)          

= 12 x^2 + 7

YS
Answered by Yusuf S. Further Mathematics tutor

6752 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

A straight line passes trough the points A(-4;7); B(6;-5); C(8;t). Use an algebraic method to work out the value of t.


The function f is given by f(x) = SQRT(2x − 5). Work out x when f(x) = 1.2


Find any stationary points in the function f(x) = 3x^2 + 2x


express z(2+i)=(1+2i)^2 in the form z=x+iy


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning