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Solve the equation:

5^x-3=7^2x+1

log₅5^x-3=log₅7^2x+1

x-3=(2x+1)log₅7

x-2xlog₅7=3+log₅7

x(1-2log₅7)=3+log₅7

x=(3+log₅7)/(1-2log₅7)

NH

Answered by Nina H. • Maths tutor

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