A particle is moving along a straight line. The fixed point O lies on this line. The displacement of the particle from O at time t seconds is s metres where s = 2t3 – 12t2 + 7t(a) Find an expression for the velocity, v m/s, of the particle at time t.

To find velocity you differentiate displacement with respect to time

Therefore ds/dt = v = (3x2)t2-(12x2)t2+7

Implying v = 6t2-24t+7

TO

Related Maths GCSE answers

All answers ▸

Solve x2 + 2x − 4 = 0 leave in simplest form.


Calculate the length of side AB (opposite) in a right angled triangle, where angle C is 32 degrees and length of BC (hypotenuse) is 8cm.


5x-7 = 3x + 3, solve x


Work out 7/8 × 3/4