Solve simultaneously 2x + 3y = 18 and y = 3x – 5 to find the value of x and y.

sub the y value into the first eqn 2x + 3(3x-5) = 18 expand the brackets 2x +9x-15 = 18 add up the x values 11x -15 = 18 add 15 to both sides to cancel it out on the l.h.s 11x = 33 divide by 11 to get value of x x = 3 put value of x into the y eqn y = 3(3) - 5 work out value of y y = 4

JG
Answered by Jessica G. Maths tutor

3389 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Fully simplify: (y^2 x y^5) / y^3


How do I know when to use SOHCAHTOA and when to use the sine or cosine rule?


Show that 12 cos 30° - 2 tan 60° can be written in the form√ k where k is an integer


Solve this equation: 5x-4=3x+7


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences