Prove that the square of an odd number is always 1 more than a multiple of 4

(2x-1)2 = 4x2- 4x + 1= 4(x2-x)+1The part of the expression which is: 4(x2-x) indicates that the value is a multiple of 4. The number 1 is then added which means that the statement 'the square of an odd number is always 1 more than a multiple of 4' is correct.

GP
Answered by Gokul P. Maths tutor

2976 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following pair of simultaneous equations: 5x+2y=8 and 2x+y=7


Solve 5x + 10 = 2x(5x + 10)


Solve for x to 3dp: x^2 + 6x + 2 = 0


How do I solve simultaneous equations?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences