Prove that the square of an odd number is always 1 more than a multiple of 4

(2x-1)2 = 4x2- 4x + 1= 4(x2-x)+1The part of the expression which is: 4(x2-x) indicates that the value is a multiple of 4. The number 1 is then added which means that the statement 'the square of an odd number is always 1 more than a multiple of 4' is correct.

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Answered by Gokul P. Maths tutor

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solve: [(3x-2)/4] - [(2x+5)/3] = [(1-x)/6]


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