Answers>Maths>GCSE>Article

Solve the simultaneous equations 3x+2y=8 and 3y+4x=11

Equal out the x terms so 12x+8y=32 and 9y+12x=33Then subtract the first equation from the secondThis gives y=1Put this value into one of the equations so 12x+8=32Solve the equation giving x as 2.

Answered by Emily P. • Maths tutor

5227 Views

See similar Maths GCSE tutors

Solve the simultaneous equations 3x+2y=8 and 3y+4x=11

Related Maths GCSE answers

What is 90 million in standard form?

Factorise and solve x^2 - 8x + 15 = 0.

Solve the simultaneous equations 3x + 2y = 4 and 4x + 5y = 17

Find the 16th term in the following sequence: 3, 5, 7, 9, 11