make x the subject of 5(x-3) = y(4-3x)

step 1 ; expand the brackets5x - 15 = 4y - 3xystep 2 ; group together x values on one side5x + 3xy = 4y + 15step 3 ; single out xx (5+3y) = 4y +15step 4 ; make x the subjectx = (4y + 15) / (5+3y)

SA
Answered by Sofia A. Maths tutor

4981 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Ian earns £420 a week after a 5% rise. What was his pay before?


Expand and simplify (x-5)(3x+3)


Solve algebraically the simultaneous equations: 6x=5-2y 12.5=3x+3y


How do you solve a quadratic equation e.g. x^2 - 5x - 14 = 0?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning