Solve the simultaneous equations for x and y: 2x+4y=-12 and y=-x-2

From the question we have y = -x - 2 so we can sub in -x-2 everywhere there is a y in the first equation.

The equation is then 2x+4(-x-2) = -12 expanding the brackets we get -2x-8=-12 which you can then rearrange to get x=2.

Finally we must remember to find the value for y as well, we can use the value for x we just found and sub it ino either equation.

Subbing into the 2nd equation we get y=-2-2 so y=-4 

DG
Answered by Daniel G. Maths tutor

4119 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

solve 2x^2+4x-7=0


Solve x^2+3x-18=0 for x


Prove that the square of an odd number is always 1 more than a multiple of 4


What are the solutions to x^2+3x+2=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning