The width of a Rectangle is 4cm shorter than its length. the rectangle has an area of 32cm2. Calculate its perimeter?
x (x-4) = 32X^2-4x-32 = 0(x-8)(x+4) = 0 x=8perimeter =8+4+4+8 = 24cm.
DH
x (x-4) = 32X^2-4x-32 = 0(x-8)(x+4) = 0 x=8perimeter =8+4+4+8 = 24cm.
