4y^2 = 256, Find a value for y

y^2 = 256/4 = 64
therefore, y = sqrt(64) = 8

KP
Answered by Kai P. Maths tutor

2957 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Make x the subject of 5(x-3) = y(4-3x)


Find the minimum value of the quadratic equation: y = x^2 + 4x - 12


Solve ((3x-2)/4) - ((2x+5)/3) = ((1-x)/6)


A circle has the equation x^2 + y^2 = 25. There is a point P on this circle with coordinates (4,3). A line is drawn tangental to the circle at point P. This line crosses the x axis at point Q. Find the co-ordinates of Q.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences