Without expanding any brackets, work out the solutions of 9(x+3)^2 = 4

To solve for x first divide both sides by 9, giving the equation:(x+3)2 = 4/9Then square root both sides, leading to:x+3 = +/- 2/3Finally subtract 3 from both sides leaving:x = -11/3 or x = -7/3

MT

Related Maths GCSE answers

All answers ▸

Find x when: (2^x)(e^(3x+1))=10. Give your answer in the form (a + ln(b)) / (c + ln(d)) , where a,b,c,d are integers.


Given that your grade for your computing is based on 5 coursework that weigh differently, and you know the results of 4: 80, 75, 50 and 90 which weighs 10%, 20%, 45% and 5%. What grade do you need in your last coursework to achieve at least a B (70%)?


If x>2y and 2x<5y, what is the range of x when y=6?


Simplify (3x+2)/(sqrt(x)-1)