Make a the subject of the formula p = (3a + 5)/ (4 - a)

We start by multiplying both sides of the equation by (4 -a). We then expand the brackets "p.(4-a)" and end up with "4p - pa". We then gather the "a's" to one side of the equation by subtracting "3a" from both sides. To leave the "a's" on their own, we subtract "4p" from both sides. We now have the following equation: " - pa - 3a = 5 - 4p". We can factorise the "a" out ending up with "a (-p - 3) = 5 - 4p". To get a alone, we can divide both sides by "(- p - 3). We have now made a the subject: a = (5 - 4p)/ (-p -3).

JP

Related Maths GCSE answers

All answers ▸

solve (5 - x)/2 = 2x - 7 to find the value of x


What is the cosine rule and when can it be used?


How do you change the subject of the formula?


How should I present my working out?