Make a the subject of the formula p = (3a + 5)/ (4 - a)

We start by multiplying both sides of the equation by (4 -a). We then expand the brackets "p.(4-a)" and end up with "4p - pa". We then gather the "a's" to one side of the equation by subtracting "3a" from both sides. To leave the "a's" on their own, we subtract "4p" from both sides. We now have the following equation: " - pa - 3a = 5 - 4p". We can factorise the "a" out ending up with "a (-p - 3) = 5 - 4p". To get a alone, we can divide both sides by "(- p - 3). We have now made a the subject: a = (5 - 4p)/ (-p -3).

JP
Answered by Juliana P. Maths tutor

4154 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations: 3x + 2y = 16 2x + 3y = 14


The functions f and g are such that f(x)=5x+2 and g(x)=-x-4. a) Find fg(x). b) Find ff(x). c) Solve fg(x) = ff(x).


How do you calculate the area of a triangle when the question tells you the length of all three sides but no angles?


Solve 2x-5=3x+4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences