Make a the subject of the formula p = (3a + 5)/ (4 - a)

We start by multiplying both sides of the equation by (4 -a). We then expand the brackets "p.(4-a)" and end up with "4p - pa". We then gather the "a's" to one side of the equation by subtracting "3a" from both sides. To leave the "a's" on their own, we subtract "4p" from both sides. We now have the following equation: " - pa - 3a = 5 - 4p". We can factorise the "a" out ending up with "a (-p - 3) = 5 - 4p". To get a alone, we can divide both sides by "(- p - 3). We have now made a the subject: a = (5 - 4p)/ (-p -3).

JP

Related Maths GCSE answers

All answers ▸

7x + 6 > 1 + 2x


how do i approach more complex algebra questions?


You are asked to choose from the meal deal at school, there are 9 varieties of sandwich, 6 varieties of snack and 8 varieties of drink. The meal deal consists of a sandwich, snack and drink - how many different combinations of meal deal are there?


Solve 5x-9=26.