Use the quadratic formula to find the solutions to x^2+2x-35=0

x=5 and x=7

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How do you change the subject of the formula?


Factorize x^2-x-20


y = p x q^(x - 1), When x = 1, y = 10, and when x = 6, y = 0.3125. Find the value of 'y' when x = 3


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